(3t-4)(t^2-5t+1)=

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Solution for (3t-4)(t^2-5t+1)= equation: 


Simplifying
(3t + -4)(t2 + -5t + 1) = 0

Reorder the terms:
(-4 + 3t)(t2 + -5t + 1) = 0

Reorder the terms:
(-4 + 3t)(1 + -5t + t2) = 0

Multiply (-4 + 3t) * (1 + -5t + t2)
(-4(1 + -5t + t2) + 3t * (1 + -5t + t2)) = 0
((1 * -4 + -5t * -4 + t2 * -4) + 3t * (1 + -5t + t2)) = 0
((-4 + 20t + -4t2) + 3t * (1 + -5t + t2)) = 0
(-4 + 20t + -4t2 + (1 * 3t + -5t * 3t + t2 * 3t)) = 0
(-4 + 20t + -4t2 + (3t + -15t2 + 3t3)) = 0

Reorder the terms:
(-4 + 20t + 3t + -4t2 + -15t2 + 3t3) = 0

Combine like terms: 20t + 3t = 23t
(-4 + 23t + -4t2 + -15t2 + 3t3) = 0

Combine like terms: -4t2 + -15t2 = -19t2
(-4 + 23t + -19t2 + 3t3) = 0

Solving
-4 + 23t + -19t2 + 3t3 = 0

Solving for variable 't'.

The solution to this equation could not be determined.

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